document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180562>Question 180562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular garden has dimensions of 15 feet by 11 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 192 square feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135322 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"area of outside edge of gravel path\" - \"area of garden\" = 192<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = width of gravel path<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(2x+15)(2x+11) - (15)(11) = 192<BR>\n" );
document.write( "4x^2+22x+30x+165 - 165 = 192<BR>\n" );
document.write( "4x^2+52x = 192<BR>\n" );
document.write( "x^2+13x = 48<BR>\n" );
document.write( "x^2+13x-48 = 0<BR>\n" );
document.write( "factoring:<BR>\n" );
document.write( "(x+16)(x-3) = 0<BR>\n" );
document.write( "x = {-16, 3}<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Tossing out the negative solution leaves us with:<BR>\n" );
document.write( "width of path = 3 feet\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );