document.write( "Question 180513: 5x-y=-18
\n" ); document.write( "4x+2y=92
\n" ); document.write( " These are both the same problem.I don't get how to do these problems.Could you explain to me how to do this type of problem please?
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Algebra.Com's Answer #135289 by Alan3354(69443)\"\" \"About 
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5x-y=-18
\n" ); document.write( "4x+2y=92
\n" ); document.write( "These are both the same problem.
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\n" ); document.write( "I think it's one problem, and you want to solve for x and y.
\n" ); document.write( "There are 2 equations and 2 unknowns, so it might work out.
\n" ); document.write( "One method it elimination. Multiply one of the eqns by something to get the same coefficients for one of the unknowns.
\n" ); document.write( "If the 1st eqn is multiplied by 2, it will have -2y in it, and the 2nd eqn has 2y also.
\n" ); document.write( "5x-y=-18 --> 10x - 2y = -36
\n" ); document.write( "10x - 2y = -36
\n" ); document.write( "4x + 2y = 92 Then add the 2 eqns
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\n" ); document.write( "14x + 0y = 56
\n" ); document.write( "x = 4 xxxxxxxxxxxxxxxxxx That's one
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\n" ); document.write( "Then sub 4 for x into an eqn to find y
\n" ); document.write( "4x+2y=92
\n" ); document.write( "16+2y=92
\n" ); document.write( "2y = 76
\n" ); document.write( "y = 38 yyyyyyyyyyyyyyyyyyy
\n" ); document.write( "That's it.
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