document.write( "Question 180502: Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle \n" ); document.write( "
Algebra.Com's Answer #135262 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip \n" ); document.write( " would have taken 2 hours less. Find the speed of his vehicle \n" ); document.write( ": \n" ); document.write( "Let s = the speed of his vehicle \n" ); document.write( "then \n" ); document.write( "(s+20) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Actual time = faster speed time + two hrs \n" ); document.write( " \n" ); document.write( "Multiply equation by s(s+20) to eliminate the denominators, results \n" ); document.write( "150(s+20) = 150s + 2s(s+20) \n" ); document.write( ": \n" ); document.write( "150s + 3000 = 150s + 2s^2 + 40s \n" ); document.write( ": \n" ); document.write( "0 = 150s - 150s + 2s^2 + 40s - 3000 \n" ); document.write( ": \n" ); document.write( "A quadratic equation \n" ); document.write( "2s^2 + 40s - 3000 = 0 \n" ); document.write( ": \n" ); document.write( "Simplify, divide by 2: \n" ); document.write( "s^2 + 20s - 1500 \n" ); document.write( ": \n" ); document.write( "Factors to: \n" ); document.write( "(s + 50)(s - 30) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "s = 30 mph is his actual speed \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "150/30 = 5 hrs \n" ); document.write( "150/50 = 3 hrs \n" ); document.write( "-------------- \n" ); document.write( "difference 2hr \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |