document.write( "Question 180502: Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle \n" ); document.write( "
Algebra.Com's Answer #135262 by ankor@dixie-net.com(22740)\"\" \"About 
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Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip
\n" ); document.write( " would have taken 2 hours less. Find the speed of his vehicle
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\n" ); document.write( "Let s = the speed of his vehicle
\n" ); document.write( "then
\n" ); document.write( "(s+20) = the faster speed
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "Actual time = faster speed time + two hrs
\n" ); document.write( "\"150%2Fs\" = \"150%2F%28%28s%2B20%29%29\" + 2
\n" ); document.write( "Multiply equation by s(s+20) to eliminate the denominators, results
\n" ); document.write( "150(s+20) = 150s + 2s(s+20)
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\n" ); document.write( "150s + 3000 = 150s + 2s^2 + 40s
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\n" ); document.write( "0 = 150s - 150s + 2s^2 + 40s - 3000
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\n" ); document.write( "A quadratic equation
\n" ); document.write( "2s^2 + 40s - 3000 = 0
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\n" ); document.write( "Simplify, divide by 2:
\n" ); document.write( "s^2 + 20s - 1500
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\n" ); document.write( "Factors to:
\n" ); document.write( "(s + 50)(s - 30) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "s = 30 mph is his actual speed
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "150/30 = 5 hrs
\n" ); document.write( "150/50 = 3 hrs
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\n" ); document.write( "difference 2hr \r
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