document.write( "Question 180502: Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle \n" ); document.write( "
Algebra.Com's Answer #135258 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle \n" ); document.write( "--------------------------- \n" ); document.write( "Steve DATA: \n" ); document.write( "distance = 150 miles ; rate = x mph ; time = d/r = 150/x hrs \n" ); document.write( "----------------------------------------------- \n" ); document.write( "Improved Steve DATA: \n" ); document.write( "distance = 150 miles : rate = x+20 ph ; time = d/r = 150/(x+2) hrs \n" ); document.write( "--------------------------------- \n" ); document.write( "Equations: \n" ); document.write( "Old Steve time - Improved Steve time = 2 hrs \n" ); document.write( "150/x - 150/(x+2) = 2\r \n" ); document.write( "\n" ); document.write( "150(x+2) - 150x = 2x(x+2) \n" ); document.write( "300 = 2(x^2+2x) \n" ); document.write( "x^2 + 2x - 150 = 0\r \n" ); document.write( "\n" ); document.write( "x = [-2 +- sqrt(4 - 4*1*-150)]/2\r \n" ); document.write( "\n" ); document.write( "x = [-2 +- sqrt(604)]/2 \n" ); document.write( "Positive solution:\r \n" ); document.write( "\n" ); document.write( "x = 11.29 mph (Old rate) \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |