document.write( "Question 180497: I have a question involving Algebra 1\r
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document.write( "A rental company charges a flat fee of x dollers plus y dollers per hour used
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document.write( "one customer used 4 hours and had a fee of 63 dollers
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document.write( "Another stayed for 6 hours and had a fee of 87 dollers\r
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document.write( "Please explain what steps i should take first and what method i must use.\r
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document.write( "please explain \n" );
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Algebra.Com's Answer #135257 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let x be the flat fee and y be the additional fee \n" ); document.write( ": \n" ); document.write( "x+4y=63.........eq 1 \n" ); document.write( "x+6y=87.........eq 2 \n" ); document.write( ": \n" ); document.write( "subtract all terms from eq 2 from eq 1 \n" ); document.write( ": \n" ); document.write( "x terms will be eliminated because x-x=0. We are left with 4y-6y=63-87 \n" ); document.write( ": \n" ); document.write( "-2y=-24 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "take y's found value and plug it into either eq 1 or 2 \n" ); document.write( ": \n" ); document.write( "I am using eq 1 \n" ); document.write( ": \n" ); document.write( "x+4(12)=63 \n" ); document.write( ": \n" ); document.write( " |