document.write( "Question 180499: There is a flat fee x plus y dollers for every hour
\n" );
document.write( "A person used 4 hours and had a fee of 63
\n" );
document.write( "another person used it for 6 hours and had a fee of 87
\n" );
document.write( "What is the value of the flat fee (x) and additional fee (y)\r
\n" );
document.write( "\n" );
document.write( "Please explain steps \n" );
document.write( "
Algebra.Com's Answer #135252 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let x be the flat fee and y be the additional fee \n" ); document.write( ": \n" ); document.write( "x+4y=63.........eq 1 \n" ); document.write( "x+6y=87.........eq 2 \n" ); document.write( ": \n" ); document.write( "subtract all terms from eq 2 from eq 1 \n" ); document.write( ": \n" ); document.write( "x terms will be eliminated because x-x=0. We are left with 4y-6y=63-87 \n" ); document.write( ": \n" ); document.write( "-2y=-24 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "take y's found value and plug it into either eq 1 or 2 \n" ); document.write( ": \n" ); document.write( "I am using eq 1 \n" ); document.write( ": \n" ); document.write( "x+4(12)=63 \n" ); document.write( ": \n" ); document.write( " |