document.write( "Question 180443: The attraction (A) betwen a magnet and a bar of iron varies inversely as the square of the distance (d) between the magnet and the bar of iron. The attraction between the two is 2 newtons when the distance is 3 cm.
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document.write( "The measure of the attractin when the distance is 0.5 cm is? \n" );
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Algebra.Com's Answer #135243 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! Ad^2=k where k is a constant \n" ); document.write( ": \n" ); document.write( "lets find k \n" ); document.write( ": \n" ); document.write( "we are given A=2 and d=3 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "so our constant k =18 \n" ); document.write( ": \n" ); document.write( "Ad=18 \n" ); document.write( ": \n" ); document.write( "now lets find A when d=.5.....remembering that in an inverse relationship when one variable increases the other decreases and vice versa. In this instance d is decreasing from 3 to .5 so we would expect A to increase \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " |