document.write( "Question 180354: A train leaves the station at noon traveling at 44 mph. One hour later, another train going 52 mph, travels north on a parallel track. How many hours will the second travel before it overtakes the first train?
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Algebra.Com's Answer #135203 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let t=number of hours that elapses before the second train catches the first (counting from when the second train leaves)\r
\n" ); document.write( "\n" ); document.write( "Distance travelled by the first train=44+44t (had 1 hour head start)
\n" ); document.write( "Distance travelled by the second train=52t\r
\n" ); document.write( "\n" ); document.write( "Now we know that when the above two distances are equal, the second train will have caught up with the first, so:
\n" ); document.write( "44+44t=52t subtract 44t from each side
\n" ); document.write( "44+44t-44t=52t-44t collect like terms
\n" ); document.write( "44=8t divide each side by 8
\n" ); document.write( "t=5.5 hours-------------------------Number of hours the second train travels before it overtakes the first\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "44+44*5.5=52*5.5
\n" ); document.write( "44+242=286
\n" ); document.write( "286=286\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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