document.write( "Question 25216: find three consecutive integers such that the sum of the first and twice the second is 17 more than twice the third. \n" ); document.write( "
Algebra.Com's Answer #13519 by Paul(988)\"\" \"About 
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Let the three consecutive numbers be, x, x+1, and x+2
\n" ); document.write( "Twice the second = 2(x+1)
\n" ); document.write( "\"is\" =
\n" ); document.write( "17 more than twice the third = 17+2(x+2)
\n" ); document.write( "Add them togeher.
\n" ); document.write( "x+2(x+1)=17+2(x+2)
\n" ); document.write( "x+2x+2=17+2x+4
\n" ); document.write( "3x+2=2x+21 --->SImplfy
\n" ); document.write( "x=19
\n" ); document.write( "19+1=20
\n" ); document.write( "19+2=21\r
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\n" ); document.write( "\n" ); document.write( "Hence the three numbers are 19, 20, and 21.
\n" ); document.write( "Paul.
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