document.write( "Question 25216: find three consecutive integers such that the sum of the first and twice the second is 17 more than twice the third. \n" ); document.write( "
Algebra.Com's Answer #13519 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the three consecutive numbers be, x, x+1, and x+2 \n" ); document.write( "Twice the second = 2(x+1) \n" ); document.write( "\"is\" = \n" ); document.write( "17 more than twice the third = 17+2(x+2) \n" ); document.write( "Add them togeher. \n" ); document.write( "x+2(x+1)=17+2(x+2) \n" ); document.write( "x+2x+2=17+2x+4 \n" ); document.write( "3x+2=2x+21 --->SImplfy \n" ); document.write( "x=19 \n" ); document.write( "19+1=20 \n" ); document.write( "19+2=21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence the three numbers are 19, 20, and 21. \n" ); document.write( "Paul. \n" ); document.write( " |