document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180329>Question 180329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mike invested a total of $14,600, part at 9% simple interest and Part 6% interest for one year. If the interest in the 9% account was $300 greater than the interest in the 6% account, how much was invested in the 9% account?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135170 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mike invested a total of $14,600, part at 9% simple interest and Part 6% interest for one year. If the interest in the 9% account was $300 greater than the interest in the 6% account, how much was invested in the 9% account? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "9% int = 6%int + 300\r<BR>\n" );
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document.write( "0.09x = 0.06(14000-x) + 300\r<BR>\n" );
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document.write( "Multiply both sides by 100 to get:\r<BR>\n" );
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document.write( "9x = 6(14000)-6x + 30000<BR>\n" );
document.write( "15x = 30000 + 84000\r<BR>\n" );
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document.write( "x = $7600 (amt. invested at 9%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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