document.write( "Question 180326: Can you please help me solve this problem?!!? \"9x%5E4=25x%5E2-16\"
\n" ); document.write( "The directions say: solve the equation by making the appropriate substitution.
\n" ); document.write( "Here is what I have so far....but I am stuck.\r
\n" ); document.write( "\n" ); document.write( "\"9x%5E4-25x%5E2%2B16=0\"
\n" ); document.write( "\"%283x%5E2%29%5E2-25x%5E2%2B16=0\"
\n" ); document.write( "\"3u%5E2-25u%2B16=0\"\r
\n" ); document.write( "\n" ); document.write( "At this point I wasn't sure. Do I use the quadratic formula??? I tried that but just got confused. Please help. Thanks.
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Algebra.Com's Answer #135151 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
9x^4=25x^2-16\r
\n" ); document.write( "\n" ); document.write( "9x^4 - 25x^2 + 16 = 0\r
\n" ); document.write( "\n" ); document.write( "Quadratic Formula:\r
\n" ); document.write( "\n" ); document.write( "x^2 = [25 +- sqrt(625 - 4*9*+16)]/18\r
\n" ); document.write( "\n" ); document.write( "x^2 = [25 +- sqrt(49)]/18\r
\n" ); document.write( "\n" ); document.write( "x^2 = [25 + 7]/18 or x^2 = [25 - 7]/18\r
\n" ); document.write( "\n" ); document.write( "x^2 = 16/9 or x^2 = 1\r
\n" ); document.write( "\n" ); document.write( "x = (4/3) or x = (-4/3) or x = 1 or x= -1
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\n" ); document.write( "Cheers
\n" ); document.write( "Stan H.
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