document.write( "Question 180326: Can you please help me solve this problem?!!? \"9x%5E4=25x%5E2-16\"
\n" ); document.write( "The directions say: solve the equation by making the appropriate substitution.
\n" ); document.write( "Here is what I have so far....but I am stuck.\r
\n" ); document.write( "\n" ); document.write( "\"9x%5E4-25x%5E2%2B16=0\"
\n" ); document.write( "\"%283x%5E2%29%5E2-25x%5E2%2B16=0\"
\n" ); document.write( "\"3u%5E2-25u%2B16=0\"\r
\n" ); document.write( "\n" ); document.write( "At this point I wasn't sure. Do I use the quadratic formula??? I tried that but just got confused. Please help. Thanks.
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Algebra.Com's Answer #135149 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
\"9x%5E4-25x%5E2%2B16=0\"
\n" ); document.write( "\"%283x%5E2%29%5E2-25x%5E2%2B16=0\"
\n" ); document.write( "\"3u%5E2-25u%2B16=0\"
\n" ); document.write( "----------------
\n" ); document.write( "Sub u for x^2
\n" ); document.write( "\"9u%5E2+-+25u+%2B+16+=+0\" You used 3u for one term, and u for the other.
\n" ); document.write( "You can factor\"
\n" ); document.write( "(9u-16)*(u-1) = 0
\n" ); document.write( "u = 1, u = 16/9
\n" ); document.write( "Then
\n" ); document.write( "x = +1, -1
\n" ); document.write( "x = +4/3, -4/3
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\n" ); document.write( "Another approach is to \"eyeball\" the 9, -25, 16 and spot that +1 and -1 are solutions, factor those out, then you have a quadratic.
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