document.write( "Question 180297: Editor of school newspaper must reduce the size of a graph to fit one column.
\n" ); document.write( "Original is 2\" x 2\", and the scale factor from the original to the reduced graph is 8:3. Find the dimensions of the graph as it will appear in one column of newspaper.\r
\n" ); document.write( "\n" ); document.write( "I have tried: 2/8 2/3 = 1/4 . 2/3 = 3/8 ???? Please help.
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Algebra.Com's Answer #135131 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1st Method:
\n" ); document.write( "If you are supposed to be reducing the dimensions you get:
\n" ); document.write( "Proportion:
\n" ); document.write( "8/3 = 2/x\r
\n" ); document.write( "\n" ); document.write( "Invert to get:
\n" ); document.write( "x/2 = 3/8\r
\n" ); document.write( "\n" ); document.write( "Multiply both sides by 2 to get:\r
\n" ); document.write( "\n" ); document.write( "x = 3/4\"\r
\n" ); document.write( "\n" ); document.write( "Ans: 3/4\" by 3/4\"
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\n" ); document.write( "2nd Method: But if you are supposed to be reducing the area, proceed
\n" ); document.write( "as follows:
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\n" ); document.write( "Original area = 2*2 = 4 sq. in.
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\n" ); document.write( "Use proportion:
\n" ); document.write( "x/4 = 3/8
\n" ); document.write( "x = 3/2 sq. in
\n" ); document.write( "---
\n" ); document.write( "Then the dimensions would be sqrt(3/2) by sqrt(3/2)
\n" ); document.write( "or (1/2)sqrt(6) by (1/2)sqrt(6)
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\n" ); document.write( "Take your choice.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "Cheers--,
\n" ); document.write( "Stan H.
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