document.write( "Question 180297: Editor of school newspaper must reduce the size of a graph to fit one column.
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document.write( "Original is 2\" x 2\", and the scale factor from the original to the reduced graph is 8:3. Find the dimensions of the graph as it will appear in one column of newspaper.\r
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document.write( "I have tried: 2/8 2/3 = 1/4 . 2/3 = 3/8 ???? Please help. \n" );
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Algebra.Com's Answer #135131 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st Method: \n" ); document.write( "If you are supposed to be reducing the dimensions you get: \n" ); document.write( "Proportion: \n" ); document.write( "8/3 = 2/x\r \n" ); document.write( "\n" ); document.write( "Invert to get: \n" ); document.write( "x/2 = 3/8\r \n" ); document.write( "\n" ); document.write( "Multiply both sides by 2 to get:\r \n" ); document.write( "\n" ); document.write( "x = 3/4\"\r \n" ); document.write( "\n" ); document.write( "Ans: 3/4\" by 3/4\" \n" ); document.write( "====================== \n" ); document.write( "2nd Method: But if you are supposed to be reducing the area, proceed \n" ); document.write( "as follows: \n" ); document.write( "------- \n" ); document.write( "Original area = 2*2 = 4 sq. in. \n" ); document.write( "---- \n" ); document.write( "Use proportion: \n" ); document.write( "x/4 = 3/8 \n" ); document.write( "x = 3/2 sq. in \n" ); document.write( "--- \n" ); document.write( "Then the dimensions would be sqrt(3/2) by sqrt(3/2) \n" ); document.write( "or (1/2)sqrt(6) by (1/2)sqrt(6) \n" ); document.write( "=================================== \n" ); document.write( "Take your choice. \n" ); document.write( "----------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "Cheers--, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |