document.write( "Question 25194: An elevator went from the bottom to the top of a tower at an average speed of 4 m/s, remained at the top for 90 s, and then returned to the bottom at 5 m/s. If the total elapsed time was 4 1/2 min., how high is the tower?
\n" ); document.write( "Can you please also give the the equation you used to solve this problem?\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #13513 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
The elvator went at 4m/s at a distacne of x
\n" ); document.write( "The elvator reutrned at 5m/s at a distance of x
\n" ); document.write( "Total time in SECONDS. because its meters per second. (4*2+1)/2=4.5*60=270s
\n" ); document.write( "270s-90s=180s\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F4%2Bx%2F5=180\"
\n" ); document.write( "4*5 =20
\n" ); document.write( "5*4=20
\n" ); document.write( "Hence the common multiple is 20\r
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\n" ); document.write( "\n" ); document.write( "\"20%28x%2F4%29%2B20%28x%2F5%29=20%28180%2F1%29\"
\n" ); document.write( "Simplfy the expression.
\n" ); document.write( "5x+4x=3600
\n" ); document.write( "9x=3600
\n" ); document.write( "x=400\r
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\n" ); document.write( "\n" ); document.write( "Hence the tower is 400m tall.
\n" ); document.write( "Paul.
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