document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180280>Question 180280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify:\r<BR>\n" );
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document.write( "11(1/n - 1) - 9/n  if n=1/101.\r<BR>\n" );
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document.write( "11(1/1/101 - 1) - 1/1/101.\r<BR>\n" );
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document.write( "We are stuck with what to do with the fractions .... I recall that 1/1/101 = 1(101) but can not remember what property to use.<BR>\n" );
document.write( "Help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135116 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify: <BR>\n" );
document.write( "11(1/n - 1) - 9/n if n=1/101. <BR>\n" );
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document.write( "If I assume 1/n-1 means (1/n)-1 I would get the following results:\r<BR>\n" );
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document.write( "11((1/n)-1) - (9/n)\r<BR>\n" );
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document.write( "= (11/n) - 11 - (9/n)\r<BR>\n" );
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document.write( "= (2/n) - 11\r<BR>\n" );
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document.write( "Now let n = 1/101\r<BR>\n" );
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document.write( "= 2/(1/101) - 11\r<BR>\n" );
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document.write( "= 202 - 11\r<BR>\n" );
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document.write( "= 191\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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