document.write( "Question 3172: there are 41 pigs and chikens on a farm. There are 100 legs counted altogether, how many of each animal are there? \n" ); document.write( "
Algebra.Com's Answer #1351 by gsmani_iyer(201)\"\" \"About 
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\n" ); document.write( " let the no.of pigs = x
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\n" ); document.write( " let the no.of chicken = y
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\n" ); document.write( " pigs have 4 legs and chicken have 2 legs each
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\n" ); document.write( " so, the equation will be as under:
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\n" ); document.write( " x + y = 41 ............. (1) given.
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\n" ); document.write( " 4x + 2y = 100 ......... (2) given.
\n" ); document.write( "(1) * 2, we get
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\n" ); document.write( " 2x + 2y = 82 ........... (3)
\n" ); document.write( "(2) - (3), we get
\n" ); document.write( " 2x = 18
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\n" ); document.write( " So x = \"18%2F2\" = 9
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\n" ); document.write( " by replacing the value of x in (1), we get
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\n" ); document.write( " 9 + y =41
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\n" ); document.write( " So y =41-9 = 32.
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\n" ); document.write( " No.of pigs = 9; chicken = 32. Answer
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