document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180227>Question 180227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the substitution method to solve the linear system<BR>\n" );
document.write( "13. 3x-y = -2<BR>\n" );
document.write( "    y = 2x+3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135086 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \text{          }\math 3x-y = -2\"><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \text{          }\math y = 2x+3\">  \r<BR>\n" );
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document.write( "Just substitute the expression given as equal to <i>y</i> in the 2nd equation into the 1st equation, thus:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \text{          }\math 3x-(2x+3) = -2\">\r<BR>\n" );
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document.write( "Now solve for <i>x</i>.  Once you have the value for x, substitute that into either of the original equations (the 2nd one gives you easier arithmetic) and compute the value of <i>y</i>.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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