document.write( "Question 180219This question is from textbook Algebra 2
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document.write( ": I am so lost on this lesson. Help please! :)\r
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document.write( "5r - 4s - 3t = 3
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document.write( "r = 3s + 1
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document.write( "t = s + r \n" );
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Algebra.Com's Answer #135057 by stanbon(75887) ![]() You can put this solution on YOUR website! 5r - 4s - 3t = 3 \n" ); document.write( "r = 3s + 1 \n" ); document.write( "t = s + r \n" ); document.write( "---------------- \n" ); document.write( "You want to have one equation with one variable. \n" ); document.write( "Find a variable that is associated with two others, like \"s\" \n" ); document.write( "r = 3s+1 \n" ); document.write( "t =s + r = s+ 3s+1 = 4s+1 \n" ); document.write( "------------------------------- \n" ); document.write( "Now substitute for \"r\" and for \"t\" in the 1st equation to get:\r \n" ); document.write( "\n" ); document.write( "5(3s+1) - 4s - 3(4s+1) = 3\r \n" ); document.write( "\n" ); document.write( "Solve for \"s\".\r \n" ); document.write( "\n" ); document.write( "15s + 5 - 4s - 12s - 3 = 3\r \n" ); document.write( "\n" ); document.write( "-s +2 = 3 \n" ); document.write( "-s = 1 \n" ); document.write( "s = -1 \n" ); document.write( "---------------- \n" ); document.write( "Substitute to solve for r and for t: \n" ); document.write( "r = 3s+1 = 3(-1) + 1 = -2 \n" ); document.write( "--- \n" ); document.write( "t = 4s+1 = 4(-1) + 1 = -3 \n" ); document.write( "============================ \n" ); document.write( "Final Answer: \n" ); document.write( "s = -1 \n" ); document.write( "r = -2 \n" ); document.write( "t = -3 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |