document.write( "Question 180195: find the equation of the line that contains the point (3,2) and is perpendicular to the line 3x+y= -3\r
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Algebra.Com's Answer #135052 by mgmoeab(37)\"\" \"About 
You can put this solution on YOUR website!
The line you're looking for passes through the point (3,2) and is perpendicular to the line 3x+y= -3
\n" ); document.write( "You're looking for the equation of the line:
\n" ); document.write( "y-Y1 = m(x-X1) since you are given point (3,2)
\n" ); document.write( "you have
\n" ); document.write( "a) y - 2 = m( x - 3)
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\n" ); document.write( "Now, you only have to look for m (the slope)
\n" ); document.write( "-Since the line is perpendicular to 3x+y= -3, then the product of the slopes of two lines will –1.
\n" ); document.write( "-Since the slope of the line 3x+y= -3 is m = -3, then the slope of the line in question is m= 1/3
\n" ); document.write( "The final step is to plug in the slope we found and the rest depends if you are asked to solve for y (b), or leave the equation in point-slope-form (a)
\n" ); document.write( "(a) y - 2 = 1/3( x - 3)
\n" ); document.write( "(b)y = 1/3x + 1\r
\n" ); document.write( "\n" ); document.write( "HOPE IT HELPS
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