document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180186>Question 180186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two metal alloys, one containing 26% copper and the other containing 54%copper are to be mixed together to get 210 oz of an alloy that is 30% copper. How much of the alloy containing 26% copper should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135032 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two metal alloys, one containing 26% copper and the other containing 54%copper are to be mixed together to get 210 oz of an alloy that is 30% copper. How much of the alloy containing 26% copper should be used?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "copper + copper = copper<BR>\n" );
document.write( "0.26x + 0.54(210-x) = 0.30*210\r<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "26x + 54*210 - 54x = 30*240\r<BR>\n" );
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document.write( "-28x = - 14*240\r<BR>\n" );
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document.write( "x = 120 oz (amt. of 26% alloy in the mixure)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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