document.write( "Question 180128: Simple Interest
\n" ); document.write( "For $1000 to grow to more than $1250 in 2 years, what must the simple interest rate be?
\n" ); document.write( "This is all I have so far and it doesn't even look right =(
\n" ); document.write( "I=PRT
\n" ); document.write( "1250=1200r(2)
\n" ); document.write( "Please help!
\n" ); document.write( "

Algebra.Com's Answer #134999 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
If $1000 grew to $1250, then \"1250+-+1000+=+250\",
\n" ); document.write( "and $250 was earned in interest
\n" ); document.write( "\"I+=+P%2Ar%2At\"
\n" ); document.write( "given:
\n" ); document.write( "\"I+=+250\"
\n" ); document.write( "\"P+=+1000\"
\n" ); document.write( "\"t+=+2\"yr
\n" ); document.write( "\"250+=+1000%2Ar%2A2\"
\n" ); document.write( "\"r+=+250+%2F+2000\"
\n" ); document.write( "\"r+=+.125\"
\n" ); document.write( "The rate is 12.5 %
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