document.write( "Question 180134: Hi I have a problem that is tricky, a bicyclist and a hiker leave the same place at the sametime and travel in the same direction. The bicyclist travels three times as fast as the hiker. At the end of 3 hrs they are 24 miles apart. How fast does the hiker travel.\r
\n" ); document.write( "\n" ); document.write( "I tried looking at all angles but could not get a suitable ,if you could provide a suitable formula using x + y. Thanks This is a uniform motion problem from a study unit book for an on line course from penn foster its algebra part 3. 2469C-1
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Algebra.Com's Answer #134989 by stanbon(75887)\"\" \"About 
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a bicyclist and a hiker leave the same place at the sametime and travel in the same direction. The bicyclist travels three times as fast as the hiker. At the end of 3 hrs they are 24 miles apart. How fast does the hiker travel.
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\n" ); document.write( "Hiker DATA:
\n" ); document.write( "rate = x mph ; time = 3 hrs. ; distance = rt = 3x miles
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\n" ); document.write( "Bicyclist DATA:
\n" ); document.write( "rate = 3x mph ; time = 3 hrs. ; distance = rt = 9x miles
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\n" ); document.write( "Equation:
\n" ); document.write( "Since they are going in the same direction:
\n" ); document.write( "3x-x = 24 miles
\n" ); document.write( "2x = 24
\n" ); document.write( "x = 12 mph (hiker's rate; extraordinary)
\n" ); document.write( "3x = 36 mph (bicyclist's rate; also extraordinary)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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