document.write( "Question 180134: Hi I have a problem that is tricky, a bicyclist and a hiker leave the same place at the sametime and travel in the same direction. The bicyclist travels three times as fast as the hiker. At the end of 3 hrs they are 24 miles apart. How fast does the hiker travel.\r
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document.write( "I tried looking at all angles but could not get a suitable ,if you could provide a suitable formula using x + y. Thanks This is a uniform motion problem from a study unit book for an on line course from penn foster its algebra part 3. 2469C-1 \n" );
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Algebra.Com's Answer #134989 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a bicyclist and a hiker leave the same place at the sametime and travel in the same direction. The bicyclist travels three times as fast as the hiker. At the end of 3 hrs they are 24 miles apart. How fast does the hiker travel. \n" ); document.write( "-------------------------------------- \n" ); document.write( "Hiker DATA: \n" ); document.write( "rate = x mph ; time = 3 hrs. ; distance = rt = 3x miles \n" ); document.write( "--------------------------- \n" ); document.write( "Bicyclist DATA: \n" ); document.write( "rate = 3x mph ; time = 3 hrs. ; distance = rt = 9x miles \n" ); document.write( "--------------------------- \n" ); document.write( "Equation: \n" ); document.write( "Since they are going in the same direction: \n" ); document.write( "3x-x = 24 miles \n" ); document.write( "2x = 24 \n" ); document.write( "x = 12 mph (hiker's rate; extraordinary) \n" ); document.write( "3x = 36 mph (bicyclist's rate; also extraordinary) \n" ); document.write( "====================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================================================== \n" ); document.write( " |