document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25152>Question 25152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 80 feet. The length of the rectangle is 2 feet less than 5 times the width. What is the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13493 by </B><A HREF=/tutors/aboutme.mpl?userid=quentin252><B>quentin252(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=quentin252><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  length + width = 80<BR>\n" );
document.write( "2.  length = 5*width - 2\r<BR>\n" );
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document.write( "1.  length = 80 - width<BR>\n" );
document.write( "2.  80 - width = 5*width - 2<BR>\n" );
document.write( "-->>  80 = 6*width - 2<BR>\n" );
document.write( "-->>  82 = 6*width<BR>\n" );
document.write( "-->>  82/6 = 41/3 = width<BR>\n" );
document.write( "-->>  length = 80 - 41/3 = 240/3 - 41/3 = 199/3<BR>\n" );
document.write( "note this = 5*(41/3) - 2 = 205/3-6/3 = 199/3\r<BR>\n" );
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