document.write( "Question 180043: Suppose that 53% of all adults in a certain community are obese and that 46% suffer from diabetes. If 26% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)? \r
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Algebra.Com's Answer #134919 by stanbon(75887)\"\" \"About 
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Suppose that 53% of all adults in a certain community are obese and that 46% suffer from diabetes. If 26% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)?
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\n" ); document.write( "General Formula:
\n" ); document.write( "P(A or B) = P(A) + P(B) - P(A and B)
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\n" ); document.write( "Your Problem:
\n" ); document.write( "P(obese or diabetes) = P(obese)+P(diabetes) - P(obese and diabetes)\r
\n" ); document.write( "\n" ); document.write( "= 53% + 40% - 26% \r
\n" ); document.write( "\n" ); document.write( "= (93-26)%\r
\n" ); document.write( "\n" ); document.write( "= 67/100
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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