document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25157>Question 25157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 21% copper to make jewelry.  How many ounces of 19% alloy must be mixed with a 25% alloy to form 78 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13489 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the 19% alloy and 78-x the 25% alloy.  Now, we should be able to write the following equation:\r<BR>\n" );
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document.write( "19%x + 25%(78-x) = 21%(78)<BR>\n" );
document.write( ".19x + 19.5 - .25x = 16.38<BR>\n" );
document.write( ".19x - .25x = 16.38 -19.5<BR>\n" );
document.write( "-.06x = -3.12<BR>\n" );
document.write( "x = 52<BR>\n" );
document.write( "78-(x) = 78-52 = 26\r<BR>\n" );
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document.write( "So, you need 52 ounces of the 19% and 26 ounces of the 25%.  I hope that is right. </SPAN>\n" );
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