document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179995>Question 179995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The simplified form of tan0/cot 0 is;<BR>\n" );
document.write( "a. 1<BR>\n" );
document.write( "b. (tan 0)^2<BR>\n" );
document.write( "c. (cot 0)^2<BR>\n" );
document.write( "d. (sin 0)(cos 0)^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134878 by </B><A HREF=/tutors/aboutme.mpl?userid=eperette><B>eperette(173)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eperette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Answer is b) (tan 0)^2\r<BR>\n" );
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document.write( "Two ways to look at it:\r<BR>\n" );
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document.write( "(1) Remember tan0 and cot0 are inverses of each other....in other words tan0=1/cot0   or cot0=1/tan0.....therefore  tan0/cot0=tan0 / (1/tan0)= tan0 * tan0= (tan 0)^2....\r<BR>\n" );
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document.write( "(2) Or tan0=(sin0/cos0)  and cot0=(cos0/sin0)....therefore tan0/cot0=(sin0/cos0) / (cos0/sin0)= (sin0/cos0)*(sin0/cos0)=(sin0)^2/(cos0)^2= (tan0)^2 </SPAN>\n" );
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