document.write( "Question 25165: Please help me solve this equation: \"1%2F%28x-1%29%2B5=11%2F%28x-1%29\". i have tried it several times and can not seem to up with the answer that is in the back of the book. i am missing a step somewhere along the line. i have repeated came up with the answer as x=-1. \n" ); document.write( "
Algebra.Com's Answer #13486 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"1%2F%28x-1%29%2B5=11%2F%28x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "There are a couple of ways to do this. Probably best is to multiply both sides by the LCD which is (x-1). This is valid, provided that x does NOT equal 1, because that would make the denominator zero, which is NEVER allowed! \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29+%2A%281%2F%28x-1%29%29%2B5%2A%28x-1%29+=%28x-1%29%2A11%2F%28x-1%29%29\"
\n" ); document.write( "\"1+%2B+5x-5+=+11\"
\n" ); document.write( "\"5x+-4+=+11\"
\n" ); document.write( "\"5x+=+15\"
\n" ); document.write( "\"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"1%2F%283-1%29+%2B+5+=+11%2F%283-1%29\"
\n" ); document.write( "\"1%2F2+%2B+5+=+11%2F2\"
\n" ); document.write( "True! It checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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