document.write( "Question 179956:  Calculate the shortest distance from the given line and point povided.\r
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document.write( "2x-y=3  (2,3)\r
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document.write( "I subtracted 2 from 2x-y=3 and got -y=-2+3,  I made them postitive and got y=1\r
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document.write( "I plugged 2 in for x then got seven, I put 2(1)-7=3 and recieved 5.      I was told this is incorrect but i dont know any other way to do it...any help would be helpful. \n" );
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| Algebra.Com's Answer #134847 by Mathtut(3670)      You can put this solution on YOUR website! find the equation of the line that passes thru (2,3) and is perpendicular to the given line \n" ); document.write( ": \n" ); document.write( "the slope of the perpendicular line will have a negative reciprical to the given line. 2x-y=3 --->y=2x-3 so m= for this line is 2. the slope for the perpendicular line is -1/2 \n" ); document.write( ": \n" ); document.write( "y-3=(-1/2)(x-2) \n" ); document.write( ": \n" ); document.write( "y-3=(-1/2)x+1--->y=(-1/2)x+4--->x+2y=8 \n" ); document.write( ": \n" ); document.write( "now we have to find the intersection of these two lines \n" ); document.write( ": \n" ); document.write( "2x-y=3....eq 1 \n" ); document.write( "x+2y=8...eq 2 \n" ); document.write( ": \n" ); document.write( "multiply eq 1 by 2 and add all terms of the equations together. \n" ); document.write( ": \n" ); document.write( "4x-2y=6....eq 1 revised \n" ); document.write( "x+2y=8....eq 2 \n" ); document.write( ": \n" ); document.write( "y terms are eliminated becaue -2y+2y=0. We are left with 4x+x=14 \n" ); document.write( ": \n" ); document.write( "5x=14 \n" ); document.write( ": \n" ); document.write( "x=14/5 \n" ); document.write( ": \n" ); document.write( "plug this value back into eq 1 or 2. I chose eq 2 \n" ); document.write( ": \n" ); document.write( "(14/5)+2y=8 \n" ); document.write( ": \n" ); document.write( "2y=26/5: \n" ); document.write( "y=26/10=13/5 \n" ); document.write( ": \n" ); document.write( "Now we can use the distance formula: we have point (2,3) and point (14/5,13/5) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "distance between point (2,3) and line 2x-y=3 is \n" ); document.write( ": \n" ); document.write( " |