document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179943>Question 179943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x+4y=22\r<BR>\n" );
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document.write( "3x + 4y=10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134846 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x+4y=22.......eq 1 <BR>\n" );
document.write( "3x+4y=10.......eq 2<BR>\n" );
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document.write( "subtract equation 1 from equation 2<BR>\n" );
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document.write( "y terms are eliminated because 4y-4y=0. We are left with 5x-3x=22-10<BR>\n" );
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document.write( "2x=12<BR>\n" );
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document.write( "take the found value of x and plug it back into either equation<BR>\n" );
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document.write( "3(6)+4y=10--->18+4y=10--->4y=-8<BR>\n" );
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