document.write( "Question 179941: Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes is doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many dimes do we have? \n" ); document.write( "
Algebra.Com's Answer #134843 by Mathtut(3670)\"\" \"About 
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Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes is doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many dimes do we have?
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\n" ); document.write( "let the number of nickels and dimes be n and d respectively
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\n" ); document.write( ".05n+.1d=6.05.........eq 1
\n" ); document.write( ".05(2n)+.1(d-10)=9.85.....eq 2
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\n" ); document.write( "rewrite eq 1 to .05n=6.05-.1d--->n=121-2d and plug the value of n which is 121-d into eq 2
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\n" ); document.write( ".1(121-2d)+.1(d-10)=9.85
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\n" ); document.write( "12.1-.2d+.1d-1=9.85
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\n" ); document.write( "-.1d=1.25
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\n" ); document.write( "d=12.5
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\n" ); document.write( "something is wrong with this problem. One of the amounts in the equation is off. there is no way to get a whole number for dimes in this scenario. Email me the correct numbers. thanks Mathtut
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