document.write( "Question 179924: Use the quadratic formula to find the roots of 3x^2+10x-5=0 \n" ); document.write( "
Algebra.Com's Answer #134818 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
3x^2+10x-5=0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B10x%2B-5+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2810%29%5E2-4%2A3%2A-5=160\".
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\n" ); document.write( " Discriminant d=160 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-10%2B-sqrt%28+160+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2810%29%2Bsqrt%28+160+%29%29%2F2%5C3+=+0.441518440112253\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2810%29-sqrt%28+160+%29%29%2F2%5C3+=+-3.77485177344559\"
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\n" ); document.write( " Quadratic expression \"3x%5E2%2B10x%2B-5\" can be factored:
\n" ); document.write( " \"3x%5E2%2B10x%2B-5+=+%28x-0.441518440112253%29%2A%28x--3.77485177344559%29\"
\n" ); document.write( " Again, the answer is: 0.441518440112253, -3.77485177344559.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B10%2Ax%2B-5+%29\"
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