document.write( "Question 179887: The length of a rectangle is 8 more than the width. The perimeter of the rectangle is 96 inches. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #134796 by HyperBrain(694)\"\" \"About 
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Let x=length
\n" ); document.write( "y=width\r
\n" ); document.write( "\n" ); document.write( "x=y+8\r
\n" ); document.write( "\n" ); document.write( "2(x+y)=96
\n" ); document.write( "x+y=48\r
\n" ); document.write( "\n" ); document.write( "Substituting x=y+8,
\n" ); document.write( "y+y+8=48
\n" ); document.write( "2y+8=48
\n" ); document.write( "2y=40
\n" ); document.write( "y=20
\n" ); document.write( "x=20+8=28\r
\n" ); document.write( "\n" ); document.write( "Therefore, the rectangle is 28 inches and the width is 20 inches.\r
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