document.write( "Question 179887: The length of a rectangle is 8 more than the width. The perimeter of the rectangle is 96 inches. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #134796 by HyperBrain(694) ![]() You can put this solution on YOUR website! Let x=length \n" ); document.write( "y=width\r \n" ); document.write( "\n" ); document.write( "x=y+8\r \n" ); document.write( "\n" ); document.write( "2(x+y)=96 \n" ); document.write( "x+y=48\r \n" ); document.write( "\n" ); document.write( "Substituting x=y+8, \n" ); document.write( "y+y+8=48 \n" ); document.write( "2y+8=48 \n" ); document.write( "2y=40 \n" ); document.write( "y=20 \n" ); document.write( "x=20+8=28\r \n" ); document.write( "\n" ); document.write( "Therefore, the rectangle is 28 inches and the width is 20 inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Power up, \n" ); document.write( "HyperBrain!\r \n" ); document.write( "\n" ); document.write( "Stop this mess! Click here \n" ); document.write( " |