document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179881>Question 179881</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028241789/algebrahomeworkh>Merril Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me solve this problem. I tried to solve it by using the given measurements to find the area and then plugging the variable into an equation that would work for the value of the variable. It did not work and left me just as confused. The problem states:\"Mr. Herrera had a concrete sidewalk built on three sides of his yard as shown at the right. The yard measures 24 feet by 42 feet. The longer walk is 3 feet wide. The price of the concrete was $22 per square yard, and the total bill was $902. What is the width of the walk on the remaining two sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134791 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "This was coming out very ugly until I realized that the sidewalk must go around the outside of the 42ft by 24ft yard rather than being a part of that area.\r<BR>\n" );
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document.write( "Let <i>x</i> feet be the dimension of the side walkways.  There are two of them so they add 2<i>x</i> feet to the overall dimension of 42 feet.  So the new long dimension is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 42 + 2x\">.  The single long walkway is 3 feet wide, so it adds 3 feet to the 24 foot dimension making 27 feet.  That means the total area is given by <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 27(42 + 2x)\">.  \r<BR>\n" );
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document.write( "Since he paid $902 for the concrete at $22/sq yard, he must have added <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 902 \div 22 = 41\text{yd^2}\"> to the area of the yard.  There are 9 square feet in 1 square yard, so he added <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 41 \times 9 = 369\text{ft^2}\"> to the area of the yard.  The original area was <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 42 \times 24 = 1008\">.  369 + 1008 = 1377. \r<BR>\n" );
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document.write( "So:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 27(42 + 2x) = 1377\">\r<BR>\n" );
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document.write( "Solve for x:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 1134 + 54x = 1377\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 54x = 243\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large x = 4.5\text{ft}\">\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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