document.write( "Question 179803: The sum of the digits of a two-digit number is 9. If the digits are reversed, the number is 27 less than the original. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #134732 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of the digits of a two-digit number is 9. If the digits are reversed,
\n" ); document.write( " the number is 27 less than the original. Find the original number.
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\n" ); document.write( "Let x = the 10's digit
\n" ); document.write( "Let y = the units digit
\n" ); document.write( "then
\n" ); document.write( "10x + y = the two-digit number
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\n" ); document.write( "\"The sum of the digits of a two-digit number is 9.\"
\n" ); document.write( "x + y = 9
\n" ); document.write( "y = (9-x)
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\n" ); document.write( "\"If the digits are reversed, the number is 27 less than the original.\"
\n" ); document.write( "10y + x = (10x + y) - 27
\n" ); document.write( "10y - y = 10x - x - 27
\n" ); document.write( "9y = 9x - 27
\n" ); document.write( "Simplify, divide by 9
\n" ); document.write( "y = x - 3
\n" ); document.write( "Substitute (9-x) for y
\n" ); document.write( "9 -x = x - 3
\n" ); document.write( "9 + 3 = x + x
\n" ); document.write( "12 = 2x
\n" ); document.write( "x = 6, then obviously y = 3
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\n" ); document.write( "63 is the original number
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"If the digits are reversed, the number is 27 less than the original.\"
\n" ); document.write( "36 = 63 - 27 \r
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