document.write( "Question 179787: A total of $50,000 is invested in two funds paying 8% and 8.5% simple interest. The annual interest is $4120. How much is invested in each fund? \n" ); document.write( "

Algebra.Com's Answer #134706 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let x be the amount invested at 8.5%. Then the amount invested at 8.0% must be $50,000 - x.\r
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\n" ); document.write( "\n" ); document.write( "The amount of interest on the 8.5% investment must then be

and the amount of interest on the 8.0% investment must be

. The sum of these two amounts is the total interest, so:\r
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\n" ); document.write( "\n" ); document.write( "Solve for x to get one of the investment amounts. Subtract that amount from 4120 to get the other amount.\r
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