document.write( "Question 179787: A total of $50,000 is invested in two funds paying 8% and 8.5% simple interest. The annual interest is $4120. How much is invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #134702 by checkley77(12844)\"\" \"About 
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.085x+.08(50,000-x)=4120
\n" ); document.write( ".085x+4,000-.08x=4120
\n" ); document.write( ".005x=4,120-4,000
\n" ); document.write( ".005x=120
\n" ); document.write( "x=120/.005
\n" ); document.write( "x=120/.005
\n" ); document.write( "x=24,000 invested @ 8.5%
\n" ); document.write( "50,000-24,000=26,000 invested @ 8%
\n" ); document.write( "Proof:
\n" ); document.write( ".085*24,000+.08*26,000=4,120
\n" ); document.write( "2040+2080=4,120
\n" ); document.write( "4,120=4,120
\n" ); document.write( "
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