document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179768>Question 179768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 60% antifreeze solution is to be mixed with a 10% antifreeze solution. In what ratio (x/y) must they be mixed to obtain a 40% antifreeze solution?(hint: Let N be the number of litres of the 40% solution) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134680 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so let N be the number of liters of 40% solution.<BR>\n" );
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document.write( "let x and y be the amount of mixture of 60% and 10% solutions respectively<BR>\n" );
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document.write( "x+y=N........eq 1<BR>\n" );
document.write( ".6x+.1y=.4N..eq 2<BR>\n" );
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document.write( "rewrite eq 1 to x=N-y and plug that value into eq 2<BR>\n" );
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document.write( ".6(N-y)+.1y=.4N<BR>\n" );
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document.write( ".6N-.6y+.1y=.4N<BR>\n" );
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document.write( "-.5y=-.2N<BR>\n" );
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document.write( "y=.4N<BR>\n" );
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document.write( "x=N-.4N=.6N<BR>\n" );
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document.write( "x/y=.6N/.4N=3/2<BR>\n" );
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document.write( "so the ratio is 3 to 2 </SPAN>\n" );
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