document.write( "Question 179764: one angle of a triangle is 20 degrees., How large is the angle formed by the bisector of the other two angles? \n" ); document.write( "
Algebra.Com's Answer #134674 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "I presume you mean that you need the measure of the angle formed by the intersection of the two bisectors of the other two angles in the triangle.\r
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\n" ); document.write( "\n" ); document.write( "If one angle of a triangle measures 20 degrees, then the sum of the other two angles must be 180 - 20 = 160 degrees because the sum of the interior angles of a triangle is 180.\r
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\n" ); document.write( "\n" ); document.write( "The bisectors of the other two angles form a triangle with vertices at the vertices of the two original bisected angles and the point of intersection of the bisectors. Each of the angles at the original veritices is one-half of the orignial angle by definition of a bisector, so the sum of these two angles is one-half of the sum of the original angles previously determined to be 160 degrees, hence the sum of the half-angles is 80 degrees.\r
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\n" ); document.write( "\n" ); document.write( "Again, since the sum of the measures of the interior angles of a triangle is 180 degrees, subtracting 80 leaves 100 degrees for the measure of the angle formed by the bisectors.\r
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\n" ); document.write( "\n" ); document.write( "John
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