document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179764>Question 179764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one angle of a triangle is 20 degrees.,  How large is the angle formed by the bisector of the other two angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134671 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets call our angles a,b and c . we will call angle a=20. since this is a bisector then b=c. we know that a+b+c=180<BR>\n" );
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document.write( "a=20.........eq 1<BR>\n" );
document.write( "b=c..........eq 2<BR>\n" );
document.write( "a+b+c=180....eq 3<BR>\n" );
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document.write( "take value of a which is 20 from eq 1 and the fact that b=c and plug that into eq 3<BR>\n" );
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document.write( "20+b+b=180<BR>\n" );
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document.write( "2b=160<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28b=80%29 ALIGN=MIDDLE  ALT=\"highlight%28b=80%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >degrees<BR>\n" );
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document.write( "solver is correct it would be <BR>\n" );
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document.write( "it is the angle formed by the bisectors they are after here.<BR>\n" );
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document.write( "That would be 180-(80/2)-(80/2)=100 degrees </SPAN>\n" );
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