document.write( "Question 179730This question is from textbook algebra structure and method
\n" ); document.write( ": can you please help me use the quadratic formula to solve the following and leave irrational roots in the simplest radical form: (((2x^2-3x+1=0))) \n" ); document.write( "
Algebra.Com's Answer #134662 by Mathtut(3670)\"\" \"About 
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\"2x%5E2-3x%2B1=0\"
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\n" ); document.write( "\"%282x-1%29%28x-1%29=0\"
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\n" ); document.write( "\"system%28x=1%2F2%2Cx=1%29\"
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B-3x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-3%29%5E2-4%2A2%2A1=1\".
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\n" ); document.write( " Discriminant d=1 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--3%2B-sqrt%28+1+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-3%29%2Bsqrt%28+1+%29%29%2F2%5C2+=+1\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-3%29-sqrt%28+1+%29%29%2F2%5C2+=+0.5\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B-3x%2B1\" can be factored:
\n" ); document.write( " \"2x%5E2%2B-3x%2B1+=+%28x-1%29%2A%28x-0.5%29\"
\n" ); document.write( " Again, the answer is: 1, 0.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-3%2Ax%2B1+%29\"
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