document.write( "Question 179732: I need to find four consecutive odd integers if three times the second number is 15 greater than twice the fourth integer \n" ); document.write( "

Algebra.Com's Answer #134641 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let the first odd iteger be x. Then the second odd integer is x + 2, the third is x + 4, and the fourth is x + 6. That's because you always add 2 to get to the next consecutive odd integer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Three times the second number is then

which is equal to two times the fourth number plus 15 or

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve this for x to get the first of the consecutive odd integers, and then add two, add two, and add two to get the other three.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "

\n" );