document.write( "Question 25093: We are solving for f. The equation is
\n" ); document.write( "1/p + 1/q = 1/f
\n" ); document.write( "if pg is common deminator then we would multiply each side by pg so
\n" ); document.write( "q+p=1/f x pg. So would I then divide each side by pg
\n" ); document.write( "so I would get q+p/pq=1/f. The answer in the book is
\n" ); document.write( "f=pq/p+q which is the opposite of what I got. Thanks for your help.
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Algebra.Com's Answer #13464 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"1%2Fp+%2B+1%2Fq+=+1%2Ff\" Add the fractions on the left sides. Common denominator is pq.
\n" ); document.write( "1) \"%28p%2Bq%29%2Fpq+=+1%2Ff\" Multiply both sides by pq.
\n" ); document.write( "2) \"%28p%2Bq%29+=+pq%2Ff\" Multiply both sides by f.
\n" ); document.write( "3) \"f%28p%2Bq%29+=+pq\" Finally, divide both sides by (p+q)
\n" ); document.write( "4) \"f+=+pq%2F%28p%2Bq%29\"\r
\n" ); document.write( "\n" ); document.write( "Notice that you could have just inverted equation 1) to arrive at the same conclusion.
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