document.write( "Question 179715: Find the distance between these two points:
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Algebra.Com's Answer #134626 by Edwin McCravy(20054)\"\" \"About 
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Find the distance between these two points:
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document.write( "There are two ways to do this:\r\n" );
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document.write( "Plot the points and connect them with a line segment:\r\n" );
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document.write( "\"drawing%28400%2C291.1%2C-4%2C7%2C-1%2C7%2C+grid%281%29%2C+line%286%2C4%2C-3%2C5%29+%29\"\r\n" );
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document.write( "Then we draw in these two line segments forming a right\r\n" );
document.write( "triangle:\r\n" );
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document.write( "We count how many units long the bottom (horizontal) side of \r\n" );
document.write( "that right triangle is and see that it is 9 units long. Then \r\n" );
document.write( "we see that the left (vertical) side of the right triangle \r\n" );
document.write( "is only 1 unit long. And the hypotenuse is the distance\r\n" );
document.write( "between the desired points.  \r\n" );
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document.write( "So we use the Pythagorean \r\n" );
document.write( "theorem \r\n" );
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document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r\n" );
document.write( "\"c%5E2=9%5E2%2B1%5E2\"\r\n" );
document.write( "\"c%5E2=81%2B1\"\r\n" );
document.write( "\"c%5E2=82\"\r\n" );
document.write( "\"sqrt%28c%5E2%29=sqrt%2882%29\"\r\n" );
document.write( "\"c=sqrt%2882%29\"\r\n" );
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document.write( "Another way is to memorize the formula\r\n" );
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document.write( "\"d=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29\"\r\n" );
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document.write( "and plug in \"x%5B1%5D=6\", \"x%5B2%5D=-3\", \"y%5B1%5D=4\", \"y%5B2%5D=5\"\r\n" );
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document.write( "\"d=sqrt%28%28%28-3%29-%286%29%29%5E2%2B%28%285%29-%284%29%29%5E2+%29\"\r\n" );
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document.write( "\"d=sqrt%28%28-9%29%5E2%2B%281%29%5E2%29%29++\"\r\n" );
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document.write( "\"d=sqrt%2881%2B1%29\"\r\n" );
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document.write( "\"d=sqrt%2882%29\"\r\n" );
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document.write( "Either way we get the same answer.\r\n" );
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document.write( "The distance is \"sqrt%2882%29\"\r\n" );
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document.write( "Edwin
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