document.write( "Question 25090: ten liters of a 4% acid soluttion must be mixed with a 10% solution to get a 6% solution how many liters of the 10% solution are needed? \n" ); document.write( "
Algebra.Com's Answer #13462 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! 10L of 4% = 4(10) \n" ); document.write( "10% =? --->10x \n" ); document.write( "6%=? ---> 6(10-x) \n" ); document.write( "4(10)+10x=6(10-x) \n" ); document.write( "40+10x=60-6x \n" ); document.write( "16x=20 \n" ); document.write( "x=1.25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence about 1.25L of solution is needed. \n" ); document.write( "Paul. \n" ); document.write( " |