document.write( "Question 25090: ten liters of a 4% acid soluttion must be mixed with a 10% solution to get a 6% solution how many liters of the 10% solution are needed? \n" ); document.write( "
Algebra.Com's Answer #13462 by Paul(988)\"\" \"About 
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10L of 4% = 4(10)
\n" ); document.write( "10% =? --->10x
\n" ); document.write( "6%=? ---> 6(10-x)
\n" ); document.write( "4(10)+10x=6(10-x)
\n" ); document.write( "40+10x=60-6x
\n" ); document.write( "16x=20
\n" ); document.write( "x=1.25\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence about 1.25L of solution is needed.
\n" ); document.write( "Paul.
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