document.write( "Question 179717: Fame is 10 years older than EJ. Five years ago, EJ was two years more than one-fourth as old as Fame. What are their present ages. \n" ); document.write( "
Algebra.Com's Answer #134618 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=EJ's age; x-5=EJ's age 5 years ago \n" ); document.write( "Then x+10=Fame's age; x+10-5=x+5=fame's age 5 years ago\r \n" ); document.write( "\n" ); document.write( "Now we are told the following: \n" ); document.write( "x-5=(1/4)(x+5)+2 multiply each term by 4 \n" ); document.write( "4x-20=x+5+8 subtract x from and add 20 to each side \n" ); document.write( "4x-20+20-x=5+8+20 collect like terms \n" ); document.write( "3x=33 divide each side by 3 \n" ); document.write( "x=11----------------------------EJ's age \n" ); document.write( "x+10=11+10=21----------------------Fame's age\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "11-5=(1/4)(21-5)+2 \n" ); document.write( "6=4+2 \n" ); document.write( "6=6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |