document.write( "Question 179717: Fame is 10 years older than EJ. Five years ago, EJ was two years more than one-fourth as old as Fame. What are their present ages. \n" ); document.write( "
Algebra.Com's Answer #134618 by ptaylor(2198)\"\" \"About 
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Let x=EJ's age; x-5=EJ's age 5 years ago
\n" ); document.write( "Then x+10=Fame's age; x+10-5=x+5=fame's age 5 years ago\r
\n" ); document.write( "\n" ); document.write( "Now we are told the following:
\n" ); document.write( "x-5=(1/4)(x+5)+2 multiply each term by 4
\n" ); document.write( "4x-20=x+5+8 subtract x from and add 20 to each side
\n" ); document.write( "4x-20+20-x=5+8+20 collect like terms
\n" ); document.write( "3x=33 divide each side by 3
\n" ); document.write( "x=11----------------------------EJ's age
\n" ); document.write( "x+10=11+10=21----------------------Fame's age\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "11-5=(1/4)(21-5)+2
\n" ); document.write( "6=4+2
\n" ); document.write( "6=6\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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