document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179666>Question 179666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times a number plus twice a second number is 41. Also, four times the first plus five times the second is 71. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134591 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three times a number plus twice a second number is 41. Also, four times the first plus five times the second is 71. Find the number<BR>\n" );
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document.write( "let a and b be our numbers<BR>\n" );
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document.write( "3a+2b=41.........eq 1<BR>\n" );
document.write( "4a+5b=71.........eq 2<BR>\n" );
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document.write( "multiply eq 1 by -4 and eq 2 by 3 and add the two equations together<BR>\n" );
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document.write( "-4(3a+2b=41)---->-12a-8b=-164<BR>\n" );
document.write( "3(4a+5b=71)------>12a+15b=213<BR>\n" );
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document.write( "-12a-8b=-164.....eq 1 revised<BR>\n" );
document.write( "12a+15b=213......eq 2 revised<BR>\n" );
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document.write( "the a terms are eliminated -12a+12a=0. We are left with -8b+15b=-164+213<BR>\n" );
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document.write( "7b=49<BR>\n" );
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document.write( "take b's value and plug it back into any equation. I chose eq 1<BR>\n" );
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document.write( "3a+2(7)=41<BR>\n" );
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document.write( "3a=27<BR>\n" );
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