document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179665>Question 179665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When twice one number is decreased by two-thirds of another number, the result is 5. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134588 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When twice one number is decreased by two-thirds of another number, the result is 5.<BR>\n" );
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document.write( "lets call our numbers a and b<BR>\n" );
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document.write( "2a-(2/3)b=5<BR>\n" );
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document.write( "so we have 6a-2b=15 after multiplying by 3<BR>\n" );
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document.write( "We have 2 unknowns and ONE equation. We need more information to obtain a solution </SPAN>\n" );
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