document.write( "Question 179663: A chemistry instructor has one solution that is 50% sulfuric acid and another
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document.write( "that is 20% sulfuric acid. How much of each should she use to make 12 liters of a solution that is 30% acid? \n" );
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Algebra.Com's Answer #134581 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! A chemistry instructor has one solution that is 50% sulfuric acid and another \n" ); document.write( "that is 20% sulfuric acid. How much of each should she use to make 12 liters of a solution that is 30% acid? \n" ); document.write( ": \n" ); document.write( "let x and y be the amount of 50% and 20% solutions respectively \n" ); document.write( ": \n" ); document.write( "x+y=12.......eq 1 \n" ); document.write( ".5x+.2y=.3(12)....eq 2 \n" ); document.write( ": \n" ); document.write( "rewrite eq 1 to x=12-y and plug it into eq 2 \n" ); document.write( ": \n" ); document.write( ".5(12-y)+.2y=3.6 \n" ); document.write( ": \n" ); document.write( "6-.5y+.2y=3.6 \n" ); document.write( ": \n" ); document.write( "-.3y=-2.4 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " |