document.write( "Question 179663: A chemistry instructor has one solution that is 50% sulfuric acid and another
\n" ); document.write( "that is 20% sulfuric acid. How much of each should she use to make 12 liters of a solution that is 30% acid?
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Algebra.Com's Answer #134581 by Mathtut(3670)\"\" \"About 
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A chemistry instructor has one solution that is 50% sulfuric acid and another
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\n" ); document.write( "let x and y be the amount of 50% and 20% solutions respectively
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\n" ); document.write( "x+y=12.......eq 1
\n" ); document.write( ".5x+.2y=.3(12)....eq 2
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\n" ); document.write( "rewrite eq 1 to x=12-y and plug it into eq 2
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\n" ); document.write( ".5(12-y)+.2y=3.6
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\n" ); document.write( "6-.5y+.2y=3.6
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\n" ); document.write( "-.3y=-2.4
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\n" ); document.write( "\"highlight%28y=8%29\"amount of 20% solution
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\n" ); document.write( "\"highlight%28x=12-8=4%29\"amount of 50% solution
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