document.write( "Question 179620: 1.3+i√5
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\n" ); document.write( "\n" ); document.write( "2.4-i√2
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Algebra.Com's Answer #134559 by Mathtut(3670) $\"\"$ $\"About$

You can put this solution on YOUR website!
I will do one. and get you started on the other.. you must multiply by the conjugate to get rid of the complex number in the denominator
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\n" ); document.write( "1.3+i√5/3-i√5
\n" ); document.write( ":so we have $\"%281.3%2Bi%2Asqrt%285%29%29%2F%283-i%2Asqrt%285%29%29\"$
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\n" ); document.write( "so the conjugate of $\"3-+sqrt+%285%29\"$ is $\"3+%2Bi%2Asqrt+%285%29\"$
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\n" ); document.write( " $\"%283.9%2B2.3i%2Asqrt%285%29-5%29%2F%289%2B5%29\"$
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\n" ); document.write( "\n" ); document.write( " $\"%281.1-2.3i%2Asqrt%285%29%29%2F14\"$
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\n" ); document.write( " 2.4-i√2/i√2 the conjugate for this is $\"-i%2Asqrt%282%29\"$ repeat what took place in the problem I just solved...multiplying both top and bottom by the conjugate\r
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