document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=179559>Question 179559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An express train and a local train both leave Gray’s Lake at 12:00 noon and head for Chicago 60 miles away. The express travels twice as fast as the local and arrives 2 hours ahead of it.  Find the speed of each train.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #134511 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=134511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "60=2R(T-2)<BR>\n" );
document.write( "60=R(T+2)<BR>\n" );
document.write( "60=2RT-4R<BR>\n" );
document.write( "60=RT+2R MULTIPLY THIS EQUATION BY -2 & ADD<BR>\n" );
document.write( "-120=-2RT-4R<BR>\n" );
document.write( "-60=2RT-4R<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "-60=-8R<BR>\n" );
document.write( "-8R=-60<BR>\n" );
document.write( "R=-60/-8<BR>\n" );
document.write( "R=7.5 MPH FOR THE LOCAL TRAIN.<BR>\n" );
document.write( "2*7.5=15 MPH FOR THE EXPRESS TRAIN.<BR>\n" );
document.write( "60=15(T-2)<BR>\n" );
document.write( "60=15T-30<BR>\n" );
document.write( "15T=90<BR>\n" );
document.write( "T=90/15<BR>\n" );
document.write( "T=6 HOURS FOR THE EXPRESS<BR>\n" );
document.write( "60=7.5(6+2)<BR>\n" );
document.write( "60=7.5*8<BR>\n" );
document.write( "60=60 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );